🏡

Home
🔥

Trends
🔎

Search
⭐️

Quizes
🙈

Privacy
📝

Terms
🍪

Cookies
👔

DMCA

Telegram Group 🔥🔥🔥 Get answers in minutes

Questions answered : 48 /50

+ 4981 more

Ask on Telegram

Answer verified

Let y[n] denote the convolution of h[n] and g[n], where h[n] = (1/2)nu[n] and g[n]
is a causal sequence. If y[0] = 1 and y[1] = 1/2, then g[1] equals

🗓 Dec 11, 2021

Answer is "0"

Comments and Discussions

You don't need to login to post your comment

Comments:

Views:

60k

Likes:

120k

125 votes

Gabriella 🌐 India

give solution please

Was this answer helpful?

135 votes

Victoria 🌐 India

can anyone share the explanation, please?

Was this answer helpful?

Was your question answered?

Want to get famous? 📸

Answer question and get 🤩 high-lighted on our homepage.

Connect with us

Company

Terms and conditions

Try Automation

About

Signup for Free

🤔 No result found

👉 Don't loose hope, Try out below methods

Feedback ( Website kaise lagi? 🤔)

Let y[n] denote the convolution of h[n] and g[n], where h[n] = (1/2)nu[n] and g[n]
is a causal sequence. If y[0] = 1 and y[1] = 1/2, then g[1] equals

Answer is "0"

Comments and Discussions

Was your question answered?

Want to get famous? 📸

Answer question and get 🤩 high-lighted on our homepage.

🤔 No result found

👉 Don't loose hope, Try out below methods

Feedback ( Website kaise lagi? 🤔)

Let y[n] denote the convolution of h[n] and g[n], where h[n] = (1/2)nu[n] and g[n] is a causal sequence. If y[0] = 1 and y[1] = 1/2, then g[1] equals

Answer is "0"

Comments and Discussions

Was your question answered?

Want to get famous? 📸

Answer question and get 🤩 high-lighted on our homepage.

Let y[n] denote the convolution of h[n] and g[n], where h[n] = (1/2)nu[n] and g[n]
is a causal sequence. If y[0] = 1 and y[1] = 1/2, then g[1] equals