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In a constant magnetic field of 0.6 Tesla along the z direction, find the value of the path integral  in the units of (Tesla m2) on a square loop of side length (1/ v2 ) meters. The normal to the loop makes an angle of 60° to the z-axis, as shown in the figure. The answer should be up to two decimal places. ____________

🗓 Apr 18, 2024

Answer is "0.15"

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Vipul ~ 🌐 India
Use stokes theorem.. Surface integral of Curl A. dS = integral of B.ds( curl of magnetic vector potential is B). (0. 6)*(1/root 2)^2 * cos (60°)= 0.15 Tm^2.

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