A function y(t) satisfies the differential equation d2y/dt2 -2 dy/dt + y = 0 and is subject to the initial conditions y(t = 0) = 0 and dy/dt (t = 0) = 1. The value of y(t = 1) is

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Bhuvna

Bhuvna

please explain answer

Aditi

Aditi

need help, explain answer

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