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Ujakar and Keshab attempted to solve a quadratic equation. Ujakar made a mistake in writing down the constant term. He ended up with the roots (4, 3). Keshab made a mistake in writing down the coeffic

2 square roots of unity are

Two gases X and Y are at same temperature and pressure. The reduced temperature of X is below unity while that of Y is above unity. Thus,

Consider a unity feedback control system with open-loop transfer function The steady state error of the system due to a unity step input is

Assertion (A): An ideal rectifier should have unity harmonic factorReason (R): An ideal rectifier should have unity displacement factor

Product of 3 cube roots of unity is/are

Sum of all cube roots of unity is

Assertion (A): A. For a unity feedback system, with , the settling time of step response is constant for all values of K ≥ 1Reason (R): The real part of the roots for all values of K ≥ 1 are negat

Statements All leaves are roots Some leaves are branches Conclusions I. some branches are not leaves. II. At least some roots are branches

Find the quadratic equations whose roots are the reciprocals of the roots of 2x2 + 5x + 3 = 0