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Soumen Sarkar Khulna ~ Khulna
🌐 India
let length of rectangle = x and breth =y therefore 2(x+y)=28, x+y=14,
side of the square=diagonal of the rectangle=sruare root of x^2+y^2 therefore area of the square=x^2+y^2, according to the question x^2+y^2=xy(1+108.1/3%)
=>12x^2+12y^2=25xy
=>12x^2+24xy+12y^2=49xy
=> 12(x^2+2xy+y^2)=49xy
=>12(x+y)^2=49xy
=>12*14^2=49xy
=>xy=48,
now (x-y)^2=(x+y)^2-4xy
=> (x-y)^2=(14)^2-4*48
=>(x-y)^2=4
=>(x-y)=2 Ana.
side of the square=diagonal of the rectangle=sruare root of x^2+y^2 therefore area of the square=x^2+y^2, according to the question x^2+y^2=xy(1+108.1/3%)
=>12x^2+12y^2=25xy
=>12x^2+24xy+12y^2=49xy
=> 12(x^2+2xy+y^2)=49xy
=>12(x+y)^2=49xy
=>12*14^2=49xy
=>xy=48,
now (x-y)^2=(x+y)^2-4xy
=> (x-y)^2=(14)^2-4*48
=>(x-y)^2=4
=>(x-y)=2 Ana.
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