The area of the square formed on the diagonal of a rectangle as its side is 108 1/3 % more than the area of the rectangle. If the perimeter of the rectangle is 28 units, find the difference between the sides of the rectangle

Comments and Answers (3)

Vivek

Vivek

how did the answer came

Andrew

Andrew

please anyone explain this answer

Soumen Sarkar Khulna ~ Khulna

Soumen Sarkar Khulna ~ Khulna

let length of rectangle = x and breth =y therefore 2(x+y)=28, x+y=14,
side of the square=diagonal of the rectangle=sruare root of x^2+y^2 therefore area of the square=x^2+y^2, according to the question x^2+y^2=xy(1+108.1/3%)
=>12x^2+12y^2=25xy
=>12x^2+24xy+12y^2=49xy
=> 12(x^2+2xy+y^2)=49xy
=>12(x+y)^2=49xy
=>12*14^2=49xy
=>xy=48,
now (x-y)^2=(x+y)^2-4xy
=> (x-y)^2=(14)^2-4*48
=>(x-y)^2=4
=>(x-y)=2 Ana.

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