Shyama and Vyom walk up an escalator (moving stairway). The escalator moves at a constant speed. Shyama takes three steps for every two of Vyom’s steps. Shyama gets to the top of the escalator aft er having taken 25 steps, while Vyom (because his slowerpace lets the escalator do a little more of the work) takes only 20 steps to reach the top.If the escalator were turned off, how many steps would they have to take to walk up

Question

Shyama and Vyom walk up an escalator (moving stairway). The escalator moves at a constant speed. Shyama takes three steps for every two of Vyom’s steps. Shyama gets to the top of the escalator aft er having taken 25 steps, while Vyom (because his slowerpace lets the escalator do a little  more of the work) takes only 20 steps to reach the top.If the escalator were turned off, how many steps would they have to take to walk up

Arkadeep Das · Accepted Answer

Speed(s):speed (v)=3:2..............(a)
Speed (s):speed(e)=25:(n-25) [where n= no of steps in E]........(b)
SIMILARLY
speed (v):speed(e)=20:(n-20)..........(c)
So equating EQ. a,b & c
(n-20):(n-25)=12/10
n=50.....(ans )

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Answer is "50"

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