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A boy writes all the numbers from 100 to 999. The number of zeroes that he uses is 'a', the number of 5's that he uses is 'b' and the number of 8's he uses is 'c'. What is the value of b +ย c-a

๐Ÿ—“ Apr 19, 2024

Answer is "380"

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Priyanshuprasun ~ Patna ๐ŸŒ India
Ans is 380
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Prateek ~ City ๐ŸŒ India
Between 100 and 199, there are 10 numbers with zeroes in ones place and hence, 90 numbers with zeroes in ones place between 100 and 999.



Between 100 and 199, there are 10 numbers with zeroes in tens place and hence, 90 numbers with zeroes in tens place between 100 and 999.



Hence, total zeroes between 100 and 999 is the sum of number of zeroes in ones place and number of zeroes in tens place.



That is, a =180.



Between 100 and 199, there are 10 fives in ones place and ten 5 in tens place. Hence, total fives between 100 and 199 is 20. Hence, between 100 and 999, there are (20รƒโ€”9)+100=280 fives(100 is added because of the hundred 5s that comes in 500รขโ‚ฌโ€œ599 in the hundreds place).



Therefore, b = 280.



Similarly, the number of 8s will be same as the number of 5s. Therefore, c = 280.



Hence, b + c - a = 280 + 280 - 180 = 380.
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Sumeet ~ India ๐ŸŒ India
Please solve this question
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Anonymous ๐ŸŒ India
Ans is 380 :)
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Anonymous ๐ŸŒ National Capital Territory of Delhi
Thanks
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Anonymous ๐ŸŒ National Capital Territory of Delhi
Nope nvm
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