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Functions can be declared to return a reference type. There are reasons to make such a declaration/Which of the following reasons are correct
The information being returned is a large enough object that returning a reference is more efficient than returning a copy.
The type of the function must be a R-value
🗓 Jul 16, 2021
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Catherine
🌐 India
like it
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Kimberly
🌐 India
Thank you so much for the answer
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