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In a BOD test using 5% dilution of the sample (15 ML of sample and 285 mL of dilution water), dissolved oxygen values for the sample and dilution water blank bottles after five days incubation at 20°C were 3.80 and 8.80 mg/L. respectively.

Dissolved oxygen originally present in the undiluted sample was 0.80 mg/L. The 5-day 20°C BOD of the sample is

🗓 Mar 11, 2025

Answer is "92 Mg/L"

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Vikram 🌐 India
Bod = dissolved oxygen * dilution factor.

D.F = 5% = 100/5 = 20.

Given D.O as 0.80 & 3.80.

Bod = .80 * 20= 16mg/l.
Bod = 3.8 * 20= 76 mg/l.
Bod = 16+76=92mg/l.
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