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The current i(t) through a 10 O resistor in series with an inductance is given by i(t) = 3 + 4 sin (100t + 45°) + 4 sin (300t + 60°) Amperes. The RMS value of the current and the power dissipated in the circuit are
🗓 Jul 16, 2021
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Allison
🌐 India
Cool if had answer
votes
Deeksha
🌐 India
Can anyone please help me with the explanation?
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