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Anonymous
π Gujarat
Given :-
Gradients
n1= 4%
n2 = -2%
Length of curve = 150m
Solution:-
Deviation angle N = |n1 - n2|
= |4% - (-2%)|
N =+6%
Now,
y = ax^2
Now Highest point on the summit curve occurs at
x= n1*L
ββββ
N
= 0.04*150
_____________
0.006
X= 100m.
Gradients
n1= 4%
n2 = -2%
Length of curve = 150m
Solution:-
Deviation angle N = |n1 - n2|
= |4% - (-2%)|
N =+6%
Now,
y = ax^2
Now Highest point on the summit curve occurs at
x= n1*L
ββββ
N
= 0.04*150
_____________
0.006
X= 100m.
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votes
Anonymous
π Rajasthan
100m
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