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Odd man out: 325, 259, 202, 160, 127, 105, 94

The interest on a certain deposit at 4.5% p.a. is Rs.202.

50

50

The interest on a certain deposit at 4.5% per annum is Rs. 2

(112+122 132 ... 202) =

(112 122 132 ... 202) =

Look at this series: 201, 202, 204, 207, ... What number sho

201, 202, 204, 207, …

What number should come next? In this series: 201, 202, 204

Find the solution

(22+ 42+ 62+ ... +202) =

(22+ 42+ 62+ ... +202) =

Find the following sum: 1/

(22 -

1 ) 1/

(42 –

1) 1/

(62 – 1

(22 -

1 ) 1/

(42 –

1) 1/

(62 – 1