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An ammeter of resistance 0.16 ohm shunted with a resistance of 0.04 ohm gives a reading of 8
A. The current in the main circuit is
16 A
24 A
40 A
20 A
A circuit whose resistance is R is connected to n similarcells.
If the current in the circuit is the same whether the cells are connected in series or in parallel, then the internal resistance r of each cell is given by
r = (1 / R)
r = (R / n)
r = nR
r = R
The potential gradient along the length of a uniform wire is 5 V permetre.
There at two points A and B on the wire which are 20 cm and 80 cm on the metre scale fitted along thewire.
The p.
d. between them will be
2 v
4 V
1 V
3 v
A voltmeter reading up to 1000 m V is calibrated with apotentiometer.
An
e. m. f. of 2.08 V is balanced across 8.4 m of thewire.
The balancing length is 3.68 m when the voltmeter reads 0.9
V. The error in the voltmeter reading is
Zero
- 0.04 V
- 0.01 V
- 0.06 V
A bettery of
e.m. f. E and in internal resistance r is being used and is supplying current i in thecircuit.
The terminal potential will be
E + ir
E - ir
E
ir - E
Two identical resistors are connected in parallel, then inseries.
The effective resistances are in the ratio
1 : 4
2 : 1
4 : 1
1 : 2
A galvanometer of resistance 98 ohm is shunted by a resistance of 2ohm.
The fraction of total current that passes through the galvanometer is
1 / 98
1 / 100
1 / 2
1 / 50
A 20 ohm resistance with an unknown resistance R in series is connected to the potentiometer arrangement having a constant current in its maincircuit.
If p.
d. across 2 ohm resistance is balanced at 300 cm length and p.
d. across R at 360 cm length, then R is
6.6 ohm
3.0 ohm
3.6 ohm
The current from the battery in the above circuit is
3.7 A
5.7 A
6.7 A
1.7 A
A voltmeter 100 V range is of 9000 ohm resistance and another voltmeter of range 80 V has a resistance of 11000ohms.
This combination is connected across 120
V.The reading of voltmeter having resistance 11000 ohm is
44 V
54 V
66 V
56 V
Two metallic wires whose masses are 12 g and 18 g have lengths in the ratio of 3 : 4. Their resistances are in the ratio of
9 : 18
27 : 32
18 : 27
4 : 3
A voltmeter reading up to 1000 m V is calibrated with apotentiometer.
An
e. m. f. of 1.08 V is balanced across 5.4 m of thewire.
The balanceing length is 4.55 m when the voltmeter reads 0.9
V. The error in the voltmeter reading is
Zero
- 0.04 V
- 0.01 V
- 0.06 V
Two wires of equal length and material X and Y have samefesistance.
The ratio of the radii of the two wires is 1 : 2. The ratio of the conductivity of X and Y is
4 : 1
1 : 4
1 : 1
1 : 2
If internal resistance of cells is large as compared to the external resistance then the cells should be connected in
partly in series and remaining with reversed terminals.
Parallel
Series
partly in series and party in parallel
When the cells of different
e. m. fs. and internal resistances are connected in parallels
the e. m. f. decreases in comparison with that for single cell
the current capacity decreases in comparison with that for single cell
the e. m. f. increases in comparison with that for single cell
the current capacity increases in comparison with that for single cell
The plates of a capacitor are charged to a potential difference of V volts and then connected across aresistor.
After one second, the potential difference between the plates is V/3, then after 2sec.
from the start, the potential difference between the plates is
2V / 3
V / 9
V / 3
V / 6
In a closed circuit the
e.m.f. and internal resistance of a battery are E and Rrespectively.
If an external resistance R is connected to the battery, the current flowing through the circuit shall be
E / R + r
Er / R
E / rR
A battery of
e. m. f. E and internal resistance r is being charged with current
i. The terminal potential will be
id - E
E - ir
E
E + ir
Mixed groups of cells will send the maximum current in the external circuit when total internal resistance is
equal to external resistance
Zero
more than external resistance
less than external resistance
A cell of
e. m. f. E is connected across resistance R. The potential difference between the terminals of a cell is found to be
V. The internal resistance of the cell must be
(E - V) / R
2(E - V) / R
(E - V) R
2 (E - V) / R V
1
2
6
12
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