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If int is 2 bytes wide.What will be the output of the program
#include <stdio.h>
void fun(char**);
int main()
{
char *argv[] = {"ab", "cd", "ef", "gh"};
fun(argv);
return 0;
}
void fun(char **p)
{
char *t;
t = (p+= sizeof(int))[-1];
printf("%s\n", t);
}
🗓 Nov 10, 2024
votes
Kimberly
🌐 India
Thank you so much for the answer
votes
Sierra
🌐 India
hmm, where is the explanation
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