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A lift descends with an acceleration of 0.5 metres/sec^2 from the top floor of a multistoried building. The time required to travel a distance of 25 metres will be

🗓 Oct 19, 2024

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Basit ~ Pakistan 🌐 India
a=0.5 m/sec^2

S=25 m

t=?

Use 2nd equation of motion s=vi*t+0.5 at^2

Put values

25=0+0.5*0.5t^2

25=0.5t^2

t^2=100

Take square rootboth sides

So t=10 sec
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