In a science lab, a student heats up a chemical from 10 °C to 25 °C which requires thermal energy of 30000 J. If mass of object is 40 kg, specific heat capacity of chemical would be
answer is 50
data
temperature initial is 10
temperature final is 25
energy is 30000
mass is 40
Q = mcdeltaT
30000=40.c.15
c=30000/40.15
c=30000/600
c=50jkgc answer
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