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Discriminant of 2x² + 5x - 1 is

🗓 Mar 16, 2025

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sunil saini ~ Jaisalmer 🌐 India
compare the given quadratic equation with the following:

(a).x^2 + (b).x + (c) = 0

(2).x^2 + (5).x + (-1) = 0

Hence, a=2, b=5 & c=-1

Therefore, Discriminant D= (b)^2 - 4.(a).(c)

D = (5)^2 - 4.(2).(-1)

D = 25 -(-8)

D = 25 + 8

D = 33
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