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The number of moles of sodium hydroxide present in 2.5 L of 0.5 M aqueous solution is
🗓 May 25, 2024
votes
Anonymous
🌐 India
Molarity = no of moles of solute / volume of
solution in litre
0.5 = no of moles of NaOH/ 2.5 L
No of moles of NaOH = 0.5 × 2.5
= 1.25
votes
Anonymous
🌐 India
I need brife explanation
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