🤔 No result found

👉 Don't loose hope, Try out below methods

Ask on Telegram
  • 💡 Search Tips
  • ➡️ Type question from start
  • ➡️ Use unique words from question
  • ❌ Don't search full question
Telegram Group 🔥🔥🔥 Get answers in minutes
Questions answered : 48 /50
Guy
Guy
Guy
Guy
Guy
+ 4981 more
Verified Answer verified

A uniform circular disk of radius R and mass M is rotating with angular speed w about an axis, passing through its center and inclined at an angle 60 degrees with respect to its symmetry axis. The magnitude of the angular momentum of the disk is,

🗓 Oct 14, 2024

Comments and Discussions

You don't need to login to post your comment

Comments:
30
Views:
60k
Likes:
120k
votes
Anonymous 🌐 Kerala
L =I(X)w+I(Y)w+I(Z)w
Magnintude of L =sq.root (I(X)w)^2+(I(Y)w)^2+(I(Z)w)^2)
I(X) =MR^2/4=I(Y)
I(Z)=MR^2/2
W(x)=wsin60°
W(y) =0
W(z)=wcos60°
When we apply these values in formula
We get after simplification
Sq. Root(((M^2×R^4×w^2)/16))×(3/4 +1))
= (MR^2w/4)(sq.root 7/2)
=(Root 7 MR^2w)/8
Was this answer helpful?
votes
Anonymous 🌐 India
Wrong Answer
Was this answer helpful?

Was your question answered?

Thanks for the feedback! ✅

Want to get famous? 📸

Answer question and get 🤩 high-lighted on our homepage.

Just Automated Logo

© 2017-2022 Foxoyo™
All rights reserved.

Facebook Connect with us