Assuming VCE sat = 0.2 V and ß = 50, the minimum base current (IB) required to drive the transistor in the given figure to saturation is

Question

Sudheer · Accepted Answer

VCE sat = 0.2 V and beta = 50

Vce = Vcc - Ic Rc

0.2= 3 - 1c(1 k)

10³ Ic = 2.8 A

Ic= 2.8 mA

Ib = Ic/beta =( 2.8/50 )* 10-³

= 0.056 × 10-³= 56 x 10-⁶

Ib = 56 μA

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Assuming VCE sat = 0.2 V and ß = 50, the minimum base current (IB) required to drive the transistor in the given figure to saturation is

Answer is "56 μA"

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