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Vipin - MIT
🌐 India
log y base b = x
b^x = y
log 625 base 25 = 2
log 961 base 31 = 2
log 841 base 29 = 2
log 625 base25-log 961 base 31+ log 841 base 29
=>log 25^2 base 25+ log 31^2 base 31 + log 29^2 base 29.
So 2-2+2=2
b^x = y
log 625 base 25 = 2
log 961 base 31 = 2
log 841 base 29 = 2
log 625 base25-log 961 base 31+ log 841 base 29
=>log 25^2 base 25+ log 31^2 base 31 + log 29^2 base 29.
So 2-2+2=2
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