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Vinayak Thote ~ Ramtek
🌐 India
The probability will be 0.0165
Step-by-step explanation:
Given
Probability of power plant over heating P( H ) = 0.15
Probability of failure of backup cooling system is P( C ) = 0.11
According to question,
These events are independent,
So
The probability of Big Problem will be that Backup cooling system fails as well as power plant over heating, that is,
P( H ) * P( C )
= ( 0.15 ) * ( 0.11 )
= 0.0165
Hence,
The probability will be 0.0165
Step-by-step explanation:
Given
Probability of power plant over heating P( H ) = 0.15
Probability of failure of backup cooling system is P( C ) = 0.11
According to question,
These events are independent,
So
The probability of Big Problem will be that Backup cooling system fails as well as power plant over heating, that is,
P( H ) * P( C )
= ( 0.15 ) * ( 0.11 )
= 0.0165
Hence,
The probability will be 0.0165
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