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A magnet of length $30\ cm$ with pole strength $10\ A-m$ is freely suspended in a uniform horizontal magnetic field of induction $40 \times 10^{-6} T$ . If the magnet is deflected by $60^{o}$ from its equilibrium position, the restoring couple acting on it is :

🗓 Feb 21, 2022

Answer is "$10.39\times 10^{-5}\ Nm$"

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Hello, please post an solution as well

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