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Priyam ~ Bhubaneswar
π India
By changing the position of hundred and tenth no. 479,736,895,978,389,675 becomes
749,376,985,798,839,765.
Then after arranging them in decending order
It becomes 985,839,798,765,749,376.
So the 3rd digit of 5th number is 4 .
i. e (7"4"9)
749,376,985,798,839,765.
Then after arranging them in decending order
It becomes 985,839,798,765,749,376.
So the 3rd digit of 5th number is 4 .
i. e (7"4"9)
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Ushen
π Odisha
Answer is "3"
Given original numbers:- 479,736,895,978,389,675
Rewritten by interchanging the digits in the tens and hundred places:- 749,376,985,798,839,765
Now Descending order of newly form numbers:- 985,839,798,765,749,376
Now: Second digit of the fifth number from right ( i.e., 839)=3
Given original numbers:- 479,736,895,978,389,675
Rewritten by interchanging the digits in the tens and hundred places:- 749,376,985,798,839,765
Now Descending order of newly form numbers:- 985,839,798,765,749,376
Now: Second digit of the fifth number from right ( i.e., 839)=3
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