Decarbonylation reaction of [cis-(CH3CO)Mn(13CO)(CO)4] yields X,Y and Z, whereX =[(CH3)Mn(CO)5]; Y = [cis-(CH3)Mn(13CO)(CO)4]; Z = [trans-(CH3)Mn(13CO)(CO)4]The molar ratio ofthe products(X : Y : Z) in this reaction is
🗓 Oct 10, 2021
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Alexandra🌐 India
Students helping students, nice idea
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Ashley🌐 India
How?
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