# The molar excess Gibbs free energy, gE, for a binary liquid mixture at T and P is given by, (gE/RT) = A . x1. x2, where A is a constant. The corresponding equation for ln y1, where y1 is the activity co-efficient of component 1, is

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**Rashmi** * *

how did the answer came

**Archana** * *

please anyone explain this answer

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