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Assuming VCE sat = 0.2 V and ß = 50, the minimum base current (IB) required to drive the transistor in the given figure to saturation is
🗓 Dec 28, 2021
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Sudheer
🌐 Telangana
VCE sat = 0.2 V and beta = 50
Vce = Vcc - Ic Rc
0.2= 3 - 1c(1 k)
10³ Ic = 2.8 A
Ic= 2.8 mA
Ib = Ic/beta =( 2.8/50 )* 10-³
= 0.056 × 10-³= 56 x 10-⁶
Ib = 56 μA
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