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If 150N of farce is applied on a spanner of 10 cm to open a nut then length of spanner when force applied on it is 60 N is

🗓 Dec 12, 2024

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suharsha 🌐 India
answer = 25 cm
explanation:
distance = 10 cm = 0.10 cm
force = 150 N
distance * force = torque
0.10m * 150 N = 15 Nm
therefore length of the spanner = 15 Nm ÷ 60 N
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Anonymous 🌐 India
why you have written 10cm as0.10cm
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Anonymous 🌐 India
How 15nm ÷60n gives 25
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Anonymous 🌐 India
15Nm ÷60n
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Anonymous 🌐 India
ANSWER IS 25
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Anonymous 🌐 India
Very good, Excellent . Keep it up 💯👍. Explanation is given in steps, so it was a excellent work.
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Anonymous 🌐 India
Thankyou soo much for helping me to solve this question
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Anonymous 🌐 India
Good
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